Telegram Group & Telegram Channel
Даны следующие таблицы:

Customers

| CustomerID |   Name   |     City      |
|------------|----------|---------------|
| 1 | John | New York |
| 2 | Jane | Chicago |
| 3 | Mark | Los Angeles |
| 4 | Sarah | San Francisco |
| 5 | Michael | Houston |

Orders

| OrderID | CustomerID | OrderDate | TotalAmount |
|---------|------------|------------|-------------|
| 1 | 1 | 2022-05-15 | 500 |
| 2 | 2 | 2022-06-20 | 750 |
| 3 | 3 | 2022-06-25 | 1000 |
| 4 | 1 | 2022-07-10 | 300 |
| 5 | 4 | 2022-08-05 | 900 |

Какой из следующих SQL запросов вернет имена покупателей, разместивших как минимум 2 заказа?

A) SELECT Name FROM Customers WHERE CustomerID IN (SELECT CustomerID FROM Orders GROUP BY CustomerID HAVING COUNT(*) >= 2)

B) SELECT Name FROM Customers JOIN Orders ON Customers.CustomerID = Orders.CustomerID GROUP BY Customers.CustomerID HAVING COUNT(*) >= 2

C) SELECT Name FROM Customers JOIN Orders ON Customers.CustomerID = Orders.CustomerID WHERE COUNT(*) >= 2

D) SELECT Name FROM Customers WHERE CustomerID IN (SELECT CustomerID FROM Orders WHERE COUNT(*) >= 2)



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Даны следующие таблицы:

Customers

| CustomerID |   Name   |     City      |
|------------|----------|---------------|
| 1 | John | New York |
| 2 | Jane | Chicago |
| 3 | Mark | Los Angeles |
| 4 | Sarah | San Francisco |
| 5 | Michael | Houston |

Orders

| OrderID | CustomerID | OrderDate | TotalAmount |
|---------|------------|------------|-------------|
| 1 | 1 | 2022-05-15 | 500 |
| 2 | 2 | 2022-06-20 | 750 |
| 3 | 3 | 2022-06-25 | 1000 |
| 4 | 1 | 2022-07-10 | 300 |
| 5 | 4 | 2022-08-05 | 900 |

Какой из следующих SQL запросов вернет имена покупателей, разместивших как минимум 2 заказа?

A) SELECT Name FROM Customers WHERE CustomerID IN (SELECT CustomerID FROM Orders GROUP BY CustomerID HAVING COUNT(*) >= 2)

B) SELECT Name FROM Customers JOIN Orders ON Customers.CustomerID = Orders.CustomerID GROUP BY Customers.CustomerID HAVING COUNT(*) >= 2

C) SELECT Name FROM Customers JOIN Orders ON Customers.CustomerID = Orders.CustomerID WHERE COUNT(*) >= 2

D) SELECT Name FROM Customers WHERE CustomerID IN (SELECT CustomerID FROM Orders WHERE COUNT(*) >= 2)

BY SQL для тестировщика


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